6d^2-25d+4=0

Solution for 6d^2-25d+4=0 equation:

6d^2-25d+4=0

a = 6; b = -25; c = +4;
Δ = b2-4ac
Δ = -252-4·6·4
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-23}{2*6}=\frac{2}{12}
=1/6
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+23}{2*6}=\frac{48}{12}
=4
$